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Lets say you have letters A-F. They are paired in groups of two across 6 rows.
group 1 is row 1-2 group 2 is row 3-4 group 3 is row 5-6.
There are 5 columns
In the first column the letters A B C D E F are there in order
In each group, one of the first two Letters that appear in column 1 have to appear in every column in one of those two rows.
In each column there cant be any repeat letters
In each group, the remaining 4 spaces must come from the remaining 4 letters not in its column 1 group. Each group cannot have more than 1 letter from outside its group.

This seems impossible. am I just retarded and cant figure it out?
no sudoku solver is able to check this for me because it wont be able to recognize that only repeats vertically are wrong. repeats horizontally are fine.

An example of all possible values is something like
AA_A_
B_B_B
CC_C_
D_D_D
EE_E_
F_F_F
its possible the letters may need to be moved to different spaces though
>>
aabba
bdcef
ccddc
dfeab
eeffe
fbacd
>>
>>16361607
>aabba
>bdcef
>ccddc
>dfeab
>eeffe
>fbacd
can you explain your methodology? I have been brainlet bashing this problem for weeks.
>>
>>16361607
I'm not kidding I really am that dumb. I need to know how, I've been trying to do this for months
>>
>>16361607
okay no, I checked the answer a couple more times and this actually fails
i wanted to believe
aabbA
bdceF
ccddc
dfeab
eeFfe
fbAcd
>>
>>16361571
maybe I forgot an instruction
>>16361607
the rule I missed is that you cant repeat a pair
Once a pair in a group is used you cant ever use it again in the sequence, so AF appears twice in the chart and it fails.
>>
>>16361571
please help me redeam
>>
>>16361607
I scared away the only anon who would help me.
>>
>>16361822
Fag
>>
File: 1723779263567175.png (415 KB, 720x715)
415 KB
415 KB PNG
>>16361824



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