So my homework has a problem on it that I think I'm solving right, but I keep getting it wrong. It's just a compound inequalitySo it's:3x+2>2x-3>x-11I know you split it up into two, so:3x+2>2x-3 and 2x-3>x-113x+2>2x-3Add three to both sides3x+5>2xSubtract 3x from both sides5>-xDivide by -1-5<xAnd 2x-3>x-11subtract xx-3>-11add 3x >-8So the answer would be something like (-8, infinity), which discounts the -5Problem is, that's not right, and I know it's not right.I don't know what I'm fucking up here. I feel like it's braindead easy and I'm going to be really mad at myself for not getting it.
>>1490495are you absolutely sure you copied down the question correctly
>>1490503I am going to post it here and make sure I did.
>>1490495You discounted wrong.You have -5<x and -8<x.So the solution is (-5, infinity), not (-8, infinity)
>>1490510I discounted wrong?I mean, that's the right answer, and I thank you, but boy I feel retarded.
>>1490511Don't feel bad, it happens to everyone. I only figured out what was going wrong when I put the entire thing into Wolfram Alpha."Discounted" maybe isn't the right word. -5<x gives (-5, inf) and -8<x gives (-8, inf). Since you need x to be in both of these intervals, you take their overlap, which is (-5, inf). Every step you yourself wrote down was correct, the error was in the part that you didn't write down. Checking mental math is hard, so you should write down every step (even the obvious ones) in detail to catch stupid errors. Because when you are smart enough to know how to solve all problems, only stupid errors remain.
>>1490527See our thing doesn't have a number line, you just write down the interval notation and it checks.Good to know.There's other shit I don't think I'm going to solve fast in this but at least nothing's taken me as long as this little chestnut has, thanks again.
dude this is math I learned in middle school
>>1490594A blessing for you.I wish you happiness and success.
