>The answer is supposed to be 58Is this order of operation bullshit some sort of common core psy-op, mandela effect. This was not a thing when I was in school.
>>526344836there are 4 backpacks though?
Real eyes will see the correct answer is 18
>>526345288Oh I didn't notice the yellow backpacks doubled up in the first part of line 3. Okay suddenly this is more work than I want to put into an obvious slide thread. Bye.
>>526344836You can't figure out the answer because the first equation amounts to 2x + y = 30. If you look at the third figure of the man/woman, the man is different (there's a black thing by his shoulder) meaning it's a different variable that you can't solve for.
>>526345288she's holding a bag in the first line, but not in the third line, with 4 bags in the middle row that makes a bag worth 6. top row is 18 (3 bags) + people so people is 4. brief case is 5.1 yellow pack + (2 briefcase x people with no yellow pack)so 6 + (10 x 4) = 46
>>526345521You lost. TRANNY.
>>526344836the answer is 6 7
>>526345521The bags don't even matter because of this >>526345511
>>526345521>3 briefcases = 15Each briefcase is worth 5>3 backpacks = 24Each backpack is worth 8>3 couples + 3 backpacks = 30each couple is worth 2>One backpack plus the product of one briefcase and one couple8 + 5 × 2>the odds of pulling a gold ball is 1/3
Yellow bag = 8Couple with yellow bag= 10Couple without yellow bag=2Case = 58+(5×2)= 18>>526345288
>>526345836>>526346007Wrong. The yellow bags/backpacks are worth 6 because the first backpack is doubled. There's no way to determine the value of the couples because of this >>526345511
>>526346115Also there are two briefcases (look closely) in the bottom equation. Not like it matters since you can't solve it to begin with.
>>526346115This is so gay. I'm out.
>>526346115Jesus, you're retarded if you think this is intractable unless you're assuming some sort of nonzero off-diagonal coefficientsAssuming the interaction effects are 0:Backpack = 6Briefcase = 5Couple = 4Backpack + 2*Briefcase * Couple = 54
>>526346640The couple can't be 4. I'll make a tentative solution which requires an assumption that the couples cannot = 1 since there is a man and a woman, and thus must at least equal 2.>Equation 1>couple = x>yellow bag = 6 (see below)>black thing by the man's shoulder = y2(x+6) + (x+6+y) = 302x + 12 + x + 6 + y = 303x + 18 + y = 303x + y = 12If x cannot be 1 (see my assumption) then it must be 2, therefore3(2) + y = 126 + y = 12y = 6 (this variable won't be used again but it was necessary to solve Equation 1)So the couple without the bag = 2>Equation 2x + x + x = 15The briefcase = 5>Equation 32x + 2x = 244x = 24x = 6The yellow backpack = 6>Final equation6 + 2(5) + 2 = ?6 + 10 + 2 = 18
>>526347187Sorry I made a mistake in the equation 1 part. X there could either be 2 or 3, there's no way to know. It can't be 4 though. If it's 2 then the answer is 18. If it's 3 then the answer is 19.
