Well /sci/, what's the correct answer?
>>167949942^4 = 16. Are there actually people on this board who can't count powers of 2?
[math]2^3 + 2^2 + 2^1 + 2^0 = 8 + 4 + 2 + 1 = f(u)[/math]
>>167949948 + 4 + 2 + 1 = 15
>>1679499414, because the answer can't be the last number and (2) is even.
>>16794994It's impossible to tell because we don't know if the first f is the same as the second f.
>>16794994l-let me call my AI friend...
Is this real?
Chat, can you ask grok if this is real?
>>16795040C
>>16795130C in hexadecimal is 12, which isn't one of the answers
>>16794994f(x) = x^3 + x^2 + x + 1 = (x^4 – 1)/(x – 1)f(2) = (2^4 – 1)/(2 – 1) = 15
>>16794994it depends if it was a Tuesday or not
>>16794994No domain for the function was defined. Sorry, lil' chuddy.
I heard they don't really give out the million dollars.
>>16800097>I heard they don't really give out the million dollars.Who is they?The CMI?CMI = Clay Mathematics InstituteAnd what megabuck?For solving a MPP?MPP = Millennium Prize Problem
>>16800166>a MPPan MPP
CMI = Clay Mathematics InstituteMPP = Millennium Prize Problem>>16800097>I heard they don't really give out the million dollars.Who is they? The CMI?And what megabuck? For solving an MPP?
>>16794994Please tell me that's at most the €500-question.
>>16802778It's a psychologically impossible question for around 95% of the population
>>16802789>>16802789Went checking and it appears to be just short of 2000 Euro, so still early on.>impossible question for around 95% of the populationI'd be surprised, if more than half the people were able to do it, but come on...
