You should be able to solve this.
Any value of n works. Set a = b = c = 0.
>>16807401Can you read?>positive integers a, b, and c
n = 1
>>168074010 is not a positive integer.
How to even approach this? :hm:>>16807470What about other n? We should prove that they don't work.
AI gave me this answer.
>>16807590nooooooo why are you solving the problem?!?!!!
You could use Excel.
>>16807590Thanks, Amadeus
>>16807474Well its not a negative integer
>>16807590fucking magic wtf
>>16807590where the hell does it get a^2 + c^2 from?
>>16808696[math]2a^2 + 3b^2 = 4c^2[/math][math]3a^2 - a^2 + 3b^2 = 3c^2 + c^2[/math]take mod 3[math]-a^2 + 0 \equiv c^2[/math][math]0 \equiv a^2 + c^2[/math]for as prone as AI is to basic fuckups it is correct here
>>16808700>for as prone as AI is to basic fuckups it is correct hereyeah it's gotten pretty good at copy pasting
>>16808700ah yes of of course (x + n * k) mod k would be = x mod k
>>16808700it's easier[math] -a^2 + 0 \equiv 2a^2 + 3b^2 \equiv 4c^2 \equiv c^2 \mod 3[/math], because [math]2 \equiv -1 \mod 3[/math] and [math]4 \equiv 1 \mod 3 [/math]. so you don't need gay math trickery for this, from the beginning look at as mod 3
>>16807590Not AI. Thanks doe.
>>16807474Yes it is. A positive integer is an integer where you don't have a negative sign next to it.
