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File: 1708404789012851.jpg (54 KB, 785x606)
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> 3^2 + 4^2 = 5^2
> 3^3 + 4^3 + 5^3 = 6^3
>3 ^4 + 4^4 + 5^4 + 6^4 = 7^4 + 143
this shit is retarded and I hope it gets patched
>>
Why should it get patched?
>odd * odd = odd
>even * even = even
so
>odd ^ n = odd
>even ^ n = even
Hence
>>odd + even + odd + even = odd + odd + even + even = even + even + even = even
Obviously those things can never be equal.
>>
>>16881555
Not OP but obviously the issue is +143.
>>
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>>16881545
>7^4 + 143
143 = 12^2 – 1
>>
>>16884068
And there it is.
Bravo.
>>
>>16881545

Sequence of squares;
1,4,9,16,25
n^2
The difference of each consecutive increase of n' is 2n-1
∑(2n−1)=n2
Sequence of summing consecutive squares:
1,,5, 14, 30, 55, 91
k=1∑nk2=6n(n+1)(2n+1)
>>
Picrel for sum of consecutive squares, now, onto the Sequence of cubes:
1,8,27,64,125 = n^3
Differences between sequence of cubes:
7,19,37,61
General form:
n^3−(n−1)^3=3n^2−3n+1
Second differences

Compute differences of 3n^2−3n+1:
12, 18, 24
Δ2(n3)=6n
Third differences
6,6
Δ3(n3)=6
Constant third difference cubic polynomial (discrete analogue of calculus)
>>
>>16884362
Summing consecutive cubes

Cumulative sums:

1, 9, 36, 100, 225
>>
>>
Now, onto the Sequence of fourth powers, sum of fourth powers, and differences of fourth powers.

Sequence of n^4
1, 16, 81, 256, 625
First differences of fourth powers
15, 65, 175, 369
So:
Δ(n^4)=4n^3 − 6n^2 + 4n−1
Second differences

50, 110,194
Δ^2( n^4)=12n^2 − 12n+2
Third differences:
60, 84
Δ3(n4)=24n−12
Fourth differences:
24
Fourth differences (constant)
Δ
4
(
n
4
)
=
24
Δ^4 (n^4)=24=4!



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