Force of gravity: [math]F = G\dfrac{m M}{r^2}[/math]

Force due to acceleration: [math]F = ma[/math]

So: [math]ma = G\dfrac{m M}{r^2} \implies a = \dfrac{GM}{r^2}[/math]

So the acceleration any object experiences doesn't depend on its mass or how "heavy" it is, only on the mass of the planet / moon / etc. For Earth this a = g.

>>16895778
Good thing the moon isn't moving, the earth doesn't exist, nor the jun and nothing is moving and the densities are the same.
Yes laymen's terms the hit the same time. The mass doesn't matter because of the inertia.
Then you get to middle school.

>>16895772
The objects themselves exert different gravitational pulls due to their mass, but these are entirely insignificant because the moon is so many orders of magnitude more massive. The moon's gravity is all that matters for the drop test.

>>16895772
heavier object has a higher gravitational pull thus more force, but also requires more force to accelerate it and it evens out, in a vacuum. on earth you have an atmosphere with air resistance which impacts lighter objects with more surface area more so the feather falls slower.