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File: 1771028049719013.jpg (51 KB, 633x623)
51 KB
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Initial axioms:
To grow as a human, one must self-reflect.
Let the extent of self-reflection be R, then:
R ~ T (R is proportional to T, where T is time spent on self-reflection)

Calculations:
T=t-w-s-r (time available for self-reflection is nothing other than life time minus time spent on work, time spent on sleep, time spent on recreation)
We assume t-w is a constant, as a person doesn’t have much power to change their life time in a positive direction and their work time in a negative direction. However, we must immediately infer that unemployment = personal growth from the above equation and axioms provided. As proof is trivial, it is left as an exercise to the reader.
r=k/s, as the less one sleeps, the more time they spend on escapism.
There is no strong correlation between s and w, as one who sleeps poorly just works the same amount of time but less efficiently and takes more breaks which is r, not w.
Differentiating T with respect to independent variable s yields:
dT/ds=-1+k/s2
Obviously it is DNE at s=0, but that does not interest us, as s>0.
-1+k/s2=0 to find relative extrema:
k=s2
s=k^½
Let’s find a second derivative to see if it’s max or min:
-2k/s3 < 0, at s=k^½, so it’s a max.
So:
sr=k
sr=s2
s2-sr=0
s(s-r)=0
s=r (one must sleep, such that they recreate as much as they sleep).

However, we worked under the assumption that r=k/s correctly models the correlation between sleep and recreation (and we will continue, as it is easier).
If suppose r=k/(s^n), s=r/n (the proof is left to the reader as an exercise).
However, what if R ~ s?

Calculations Part II:
What I mean by R ~ s is something like R=KTs meaning that the less one sleeps, the less efficient is their process of self-reflection.
Thus, R max, when is Ts max.
Recall T definition:
T=(C-s-k/s)
C is just a constant that is equal to t-w.
Differentiating Ts yields:
T+s(dT/ds)
C-s-k/s-s+k/s
C-2s
Second derivative is obviously negative, so:
C-2s=0 (max of T)
C=2s
s=C/2
>>
chatgpt thread



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