If (2^15-1)=32,767 where xy=32,767Find a number x where: 1<x<(2^(32,767)-1) and x is divisible by 2^(32,767)-1
>>77996401Sorry 2^(32,767)-1 is divisible by x
>>77996401>basic>shit i never seen beforeOk
>>77996401We are not doing your math homework
>>77996438It's so fucking easy are you just a retard?
>>77996440Can't do it chud? Lmao low IQ don't ever come over to /sci/, fag.
15=5*3(2^(5)-1)*(1+2^5+2^(2(5)))=31*105731*1057=32,7672^(31*1057)-1=(2^(31)-1)*(1+2^(31)+2^(2(31))+...+...)x=(2^(31)-1))
>>77996441Get better bait next time
