How on earth would you go about solving that integration? I have no idea how to approach it, since it doesn't seem to fit any of the usual formulae.
>>16258219Express cos(x) via Euler's identity in terms of exponentials. Integrating exponentials is trivial.
>>16258219double partial integration.
>>16258219Im(exp(1+i)x)
>>16258219put it in a computer and get an answer as accurate as i want
>>16258219You know how in integrals of cosx goes cosx, sinx, -cosx, etc. and how the derivatives of e^3x goes e^3x, 3e^3x, 9e^3x? Just integrate by parts twice, it's really basic. You get S = [___] - 9S, which means S = 1/10[_____], which is the answer you got.
>>16259299this is isn't an uncommon thing to see btw
>>16258219This cannot be done. It would have to involve a Gaussian error function. Google Aquintology
e3x[ eix + e-ix]/2->e(3+i)x/(2{3+i})+e(3-i)x/(2{3-i})Now work imaginary numbers out of denominator
