Does anyone have that Professor Layton fan art where his top hat is drawn going all the way up to the sky? I can't find that in Safebooru, Danbooru, Gelbooru, Pixiv, Tumblr, Twitter, Reddit, etc. Thank you.
Much appreciated!
>>1579614how will action figures help you covert to a sticker
>>1579620Pics of them, I need a bunch to make a pack of stickers
>>1579622To create AI slop you mean.
>>1579625Is this AI slop in the room with you right now?
>>1579614>>>/a/291910867
Can someone help generate an image with ChatGPT? https://chatgpt.com/imagesUse the attached image with this prompt:**Image 1:** Chun-Li render. Keep her face, hair, ornaments, jewelry, nails, physique, swimsuit top, photorealistic style, lighting, and background.Edit Image 1 into a new full-body portrait. Change only the pose, framing, and expression. Ignore the pose and head position in Image 1.**Framing:** Full body, head to toe, both feet and ground visible. Tall portrait, camera at chest height, perfectly level. 50mm lens, natural proportions, legs not shortened.**Pose:** Relaxed standing, weight even on both feet, shoulder-width apart, spine vertical. Left hand on hip, elbow slightly out. Right arm hangs relaxed, fingers softly curled. Hands empty: no drink or objects. Head, shoulders, torso, and hips face the camera squarely, shoulders level. Exactly two arms, two legs, five fingers per hand.**Head and gaze:** Head upright and centered, chin level, eyes and ears at the same height, looking straight into the lens.**Expression:** Affectionate and warm, softer than Image 1: gentle smile, tender eyes, relaxed cheeks, symmetrical face.Comment too long. Click here to view the full text.
>>1579592Use can use AI yourself. If you ran out of credits you can pay money, this board is for requests, not begging for money like a homeless drug addict
>>1579592/r/ literally died because of this bullshitHoly shit, kys.
>>1579594>>1579596You know what, youre right. This is a garage request and I should have just waited until tomorrow. There are actual requests here and im just being impatient and annoying. It just took words of wisdom from you to realize how retarded i was being.
>>1579592>Use the attached image with this prompt:There's lots better AI-generated image galleries at e-hentai.org under their AI images category for Chun-Li or other members
>>1579592Qwen 2.1 locally on Comfyui. Even a mid tier pc can handle a local image editor, you don't need online tools.>>1579596/r/ had porn gens of real ppl and a law passed. this is just a sfw pose of Chun Li, it's harmless, and she's not real.In truth though /r/ was already dead, the ai porn requests totally hijacked the board, I think they would have deleted it even without a new law. I know I would have.
I don't know what happened, but my ping to online games spiked on October 9th around evening to 156ms to San Jose. According to Exitlag, it usually stayed around 106ms.The following day, the ping lowered to 125 but it has remained at that number ever since.I know this is a long shot but I'm not getting any answers from either my ISP or Exitlag support. I'm from South America.Maybe an undersea cable? Anyone else from SA experiencing the same?
I’ll be taking that image
>>1579010Could be a list of things ranging from the game servers to your internet connection. Is it just that game or does it affect other apps as well?
bump
I'm a uni student but I struggle with the basicsI was supposed to be calculating something completely unrelated but I got stuck in the basics of how triangles work.I can't move on unless I knowI wrote down my questions in picrel
>>1578994It's pretty much this >>1578996When you're given hard numbers, the diagram is just a visual aid. The numbers are always true and that's what matters. Nobody cares if the center line is 5mm to the right and at a tiny diagonal angle as long as there's the 90 degree box symbol and a length (or a derivable length, like if you were just given 2 and sqrt 3, the only correct solution is 1 because numbers > diagram)
>>1579135I think >>1579015 assumed that it was an equilateral triangle to start with, but your image does not assume that. It just provides a triangle with a side 2, one angle of 60 degrees, a height of sqrt(3) and a partial angle of 30 degrees. You could hypothetically grab point C and drag it leftwards or bring it closer to D, and as long as it's moved on that line the other known numbers won't change. If you take C a mile to the left, it would most certainly not be an equilateral triangle.As for your question:Assuming ABC is an equilateral triangle, AB=AC. You drop a height from point A to BC, marking the intersection at D. Angles ADB and ADC are 90 degrees, since it's a height. Angles ACD and ABD are 60 degrees from it being an equilateral triangle. Triangles ACD and ABD are congruent for having two pairs of identical sides (AD shared between both, AB=AC), and having 2 (technically 3) identical angles (ADB=ADC and ABD=ACD). The implications of congruency: ABD and ACD are the same triangle, but mirrored. Angles BAD and CAD are identical, meaning that the height is an angle bisector - angles BAD=CAD=30 degrees. Sides BD=CD, meaning the height is also a median, splitting BC into two identical sections.This can be done with all three vertices due to symmetry, hence in an equilateral triangle each height is also the median and angle bisector.I'll address the question in the original image in the following reply.
>>1579222I'd like to correct my wording/translation mistake, the term is "altitude" rather than "height".>>1578994Let's answer the question about the ABD triangle with angles 30-60-90, with the side opposite the 90 degrees angle being of length 2. Let's ignore point C because it's outside.Are you familiar with the law of SINES? It says that in any triangle, the ratio of each side divided by the sine of its opposite angle is the same. That means that AB/sin(ADB) = BD/sin(BAD) = AD/sin(ABD). If we apply numbers to these equations, we get: 2/sin(90°) = BD/sin(30°) = AD/sin(60°). sin(90°)=1, so the ratio is just 2. sin(30°)=1/2, so BD/0.5=2 => BD=1. That's exactly what you were looking for. You can do the same with sin(60°) to find AD being sqrt(3). To verify your conclusion, you can do Pythagoras on the three lengths of a right angle and find that indeed AB^2=BD^2+AD^2 (4=1+3).Center point of the whole triangle. This extra question is tricky, because triangles have several different centers, so you have to be more precise. If I'm not mistaken, the intersection of the three medians, called centroid, splits the medians in a 2:1 ratio. If X is supposed to be the centroid, then XD is half the length of AX.There are also the orthocenter, the intersection of the three altitudes which might actually be outside the triangle, and the incenter, the intersection of the three angle bisectors, which is the center of the trapped circle, but has no inherent ratio constraint.In the case of an equilateral triangle, the three aforementioned centers align, and due to the quality of the centroid, X would still split AD into a ratio of 2:1.I'll be around if you have more questions.
>>1579223>>1579222Thank you for this anon ( abit late)
>>1578994The center of the triangle (centroid) absolutely does NOT half the line AD. In fact, you will find that there's a 2:1 ratio between the segments partitioned by the perpendicular bisectors and the center. I recommend the book "Geometry by It's History" it'll walk you through everything you need to know and more. Work through that and have AI explain anything you don't understand.
sup /wsr/, I'd like to get the whole set of photos & music pieces present on the Voyager Golden RecordsApparently some photos are under copyright and NASA has not published them, and I couldn't find any "Voyager set" online that didn't just copy NASA's website
Bump
post loli
>>1578253
>>1578276Isn’t there worksafe loli?
Stumbled upon this image, but I can't seem to find the source or if there's more of the character. Reverse image search has only led to pintrest and tiktok redraws for me.
>>1579577I tried the same thing and couldn't find it. I don't know you but that's the first time I find myself thinking... How the algorithm got shittier just to find some good reverse image search results, and only wants to shove the same thing.Bump
>>1579577https://x.com/heytherenrds/ might be a good fit if I had to be honest? But just to be clear, there are some stuff that are suggestive (just giving that out as a warning just in case.)
>>1579584>https://x.com/heytherenrds/Yeah heidi is the artist, if you look through his stuff you might find it again.
Years ago there was some sort of post on tumblr or reddit or some stupid site like that which went along the lines of>American goes to the ER in Europe>Gets treatment>Asks the doctor how much it's going to set him back>Doctor looks at him with horror>"This is a *hospital*"I'm trying to find that exact original text. Help me out?
>>1578937Here you go
>>1579020No, that's not it. Try reading the OP.
>>1578937Bump!
Bump! :D
Bump!
Trying to find a meme of a guy pointing to his head thats kind of framed/posed like this. Its not roll safe, he was black too.
requesting graphs, charts, flowcharts, infographics, etc
>>1579595So THAT how it works in Android
>>1579632
>>1579633
>>1579634
>Readscomiconline is dead>Batcave is deadWhere do I read comics now?
That’s the neat part. You don’t.
>>1579593perhaps? https://fmhy.net/reading#comics
why do you want to read tranny fanfiction?
>>1579607Whoa, thanks a lot, Anon. Talk about going above and beyond. I really appreciate this. >>1579610Lust takes you to dark places.
Dragon's Crown Pro (PS4) got a recomp/port but i can't find a ROMcan you help me out? i couldn't find anything on /t/ nor archive org
>>1579621https://minerva-archive.org/
>>1579627couldn't find it on therebut nevermind, found a torrent of it on 1337x tothx anyways
Best anime for an inebriated mind?
>>1579582Love Hina (2000)
>>1579582Shikanoko Nokonoko Koshitantan
>>1579582Excel Saga
>>1579582Ixion Saga
There's this vidya webm i saw on /v/ of a loli who walks up to the screen and then goes back. I remember reverse searching it and it is an old non-h game that apparently isn't yet fully translated and is the second entry of it's franchise. It kinda looked like the OP gif, first person and all, but it was in a box UI and the pixel art was a lot more retro looking. I completely forgot the name, can anyone help me?
I have found it. It was the Wonder Project Series.
